Problema Solution
The dimensions of a rectangle are such that it's length is 3 in. more than its width. If the length were doubled and if the width were decreased by 1 in., the area would be increased by 234 in ^2. What are the length and width of the rectangle?
Answer provided by our tutors
1)
length = 3 + (breadth = x ) = 3+x
if new lenght = 2old length = 2(3+x)
and width = old breadth - 1 = x - 1
area increases by 234 inch2
so according to question
(3 +x)x + 234 = 2(3+x)(x - 1)
=> 3x + x2 +234 = -6 + 6x - 2x + 2 x2
=> x2 + x - 240 = 0
so x = 15 inch = old width
and y = 3 + 15 = 18 inches = old length