Problema Solution
The deminsions of a rectangle are such that its length is 7 Inches more than its width. If the length were doubled and if the width were decreased by 3 Inches the area would be increased by 68 Inches ^2 (squared) What are the length and width of the rectangle
Answer provided by our tutors
The deminsions of a rectangle are such that its length is 7 Inches more than its width
L = b + 7
area = L * ( L - 7 )
- ( L * ( L - 7 ) ) + ( 2L ( L - 3 - 7 ) = 68
7L + L^2 - 20 L =68
L^2 -13L-68 =0
L^2 - 17L + 4L -68 =0
( L - 17 ) (L + 4) =0
LENGTH CANT BE NEAGATIVE
SO, L = 17 INCHES , WIDTH = 17 - 7 =10 INCHES