Problema Solution

in a set of 100 act scores, where the mean is 22 and the standard deviation is 3.32, how many scores are expected to be lower than 18.68?

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in a set of 100 act scores, where the mean is 22 and the standard deviation is 3.32, how many scores are expected to be lower than 18.68?

z=(18.68-22)/3.32.

=-1.

P(z<-1)=0.1587.

Number of scores expected to be lower than 18.68=0.1587*100.

=15.87 or say 16.