The units digit f a three-digit-number is twice the tens digit. If the digits were reversed, the number is reduced by 297. Find the sums of the digits.

Solution:

The number is ABC

So

C=2B

100A+10B+C - (100C+10B+A)=297

So

A=5

B=1

C=2

So 5+1+2=8, sum =8