Problema Solution
The Sum of the squares of two consecutive odd intergers is 74 find the two intergers.
Answer provided by our tutors
let the number be
x and x+2
so
x2 + (x+2)2 = 74
=>2 x2 + 4x - 70 = 0
=>x = 5
is the answer so answer is
5 and 7
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