Problema Solution
a racquetball court has a perimeter of 120 feet with a length that is twice the width. Find the length and width of the court?
Answer provided by our tutors
P = 120 ft.
L = 2W
2L + 2W = P
2(2W) + 2W = 120
4W + 2W = 120
6W = 120
W = 120 / 6
W = 20
L = 2(20)
L = 40
The length is 40 ft. and the width is 20 ft.