Problema Solution
a jeweler needs to mix an alloy with a 16% gold content and an alloy with a 28% gold content to obtain 32 ounces of a new alloy with a 25% gold content. How many ounces of each of the original alloys must be used.
Answer provided by our tutors
x(.16) + (32-x).28 = (32).25
.16x + 8.96 - .28x = 8
-.12x = -.96
x = 8
8oz (16%) + 24oz (28%) = 32oz(25%)