Problema Solution
A number y varies inversely as the square of x. If y = 2 when x = 6, what is y when x = 3?
Answer provided by our tutors
y = k / x^2
2 = k/6^2
2 = k/36
72 = k
y = k /3
y = 72/3
y = 24
A number y varies inversely as the square of x. If y = 2 when x = 6, what is y when x = 3?
y = k / x^2
2 = k/6^2
2 = k/36
72 = k
y = k /3
y = 72/3
y = 24