Problema Solution
The sum of three numbers is 18. Twice the smallest is 5 less than the largest, and the sum of the largest and smallest is 11. Use a linear system in three variables to find the three numbers.
Answer provided by our tutors
let three numbers be a
we have
a+b+c=18
2a = c-5
a+c = 11
a+c = 11 ==> a = 11-c
and 2a = c-5 ==> 2(11-c) = c-5 ==> 22-2c = c-5
==> 27 = 3c ==> c = 9
==> a = 11-c = 11-9 = 2
Hence, a+b+c=18 ==> b = 18-11 = 7
HEnce, a=2,b=7 and c=9
musica gratis