Problema Solution
How many liters of a 70% acid solution must be mixed with a 25% acid solution to get 360 L of a 60% acid solution?
Answer provided by our tutors
How many liters of a 70% acid solution must be mixed with a 25% acid solution to get 360 L of a 60% acid solution?
x+y=360.
0.7x+0.25y=0.6*360.
0.7x+0.25(360-x)=216.
0.7x+90-0.25x=216.
0.45x=216-90.
0.45x=126.
x=126/0.45
=280.
y=360-280=80 liters.
70% acid solution in liters=280.
25% acis solution in liters =80.