A Simple space consist of four simple event. Find the Probability assignment of each P(e1)=2p(e2)=1/3P(e3)=1/5P(e4)

Solution:

P(e1)+P(e2)+P(e3)+P(e4)=1

So

P(e1)+0.5P(e1)+3P(e1)+5P(e4)=1

P(e1)=2/19

So

P(e1)=2/19

P(e2)=1/19

P(e3)=6/19

P(e4)=10/19