Problema Solution
The perimiter of a rectangle playing field is 244 feet. If it's length is 2 feet longer than twice the width, what are the dimensions of the field
Answer provided by our tutors
let width = x feet
length = 2x + 2 feet
perimeter = 2x+ 4x+4
=> 6x + 4 = 244
=> x = 40 feet
width = 40 feet
length = 82 feet