Problema Solution
How many gallons of a 60% antifreeze solution must be mixed with 80 gallons of a 30% antifreeze to get a mixture that is 50% antifreeze?
Answer provided by our tutors
LET X BE THE AMOUNT OF ANTI FREEZE REQUIRED
nOW WE KNOW THW AMOUNT OF ANTI FREEZE EXISTS BEFORE THE MIXTURE TAKES PLACE HAS TO EQUALTHE AMOUNT OF PURE ANTIFREEZE THAT EXISTS AFTER THE MIXTURE TAKES PLACE SO
0.60X+0.30*80=0.50(80+X)
0.60X+24=40+0.50x
0.10X=16
X=160(SUBSTITUTING THE VALUE IN EQUATION)
NOW 0.60*160+24=0.50*240
96+24=120
HENCE 120 GALLONS OF 60% ANTIFREEZE REQUIRED