This one has me stumped: "If 6 is subtracted from the third of three consecutive odd integers and the result is multiplied by 2, the answer is 23 less than the sum of the first and twice the sum of the second of the integers. Find the integers."

Let the integers be

x, x+2, x+4 ............like 3 , 3+2 , 3+4

2*(x+4 -6)= x + 2(x+2)-23

2*(x-2) = x+2x+4-23

2x-4 = 3x-19

3x-2x= 19-4

x= 15

The numbers are 15, 17, 19