Problema Solution
Hi can you please help me with this question, graph the equation equal to: 2x^2+2y^2-3x-5y+3=0 and find the center and radius. Thank you all your help...
Answer provided by our tutors
2x^2+2y^2-3x-5y+3=0
Taking 2 as common .
(x^2+y^2-3x/2-5y/2+3/2)=0
(x^2-2*x*3/4+(3/4)^2+y^2-2*y*5/4+(5/4)^2=-3/2+(3/4)^2+(5/4)^2.
(x-3/4)^2+(y-5/4)^2=5/8.
centre (3/4,5/4).
radius =sqrt (5/8) =0.79.