
find two integers whose product is 299 such that one of the integers is three less than twice the other integer
Q. let one of the two integers be x and other be y.
according to question
y = 2x3
give that xy =299
=> x(2x3) =299
=> 2x^2  3x 299 =0
=> x =13 or 11.5
since x is an integer x cant be 11.5 hence x =13 and y =23
← Previous Problem  Next Problem → 