Problema Solution
if an object is thrown vertically upward with an initial velocity of v, from an original position of s, the height h at any time t is given by: h=-16t^2+vt+s (where h and s are in ft, t is in seconds and v is in ft/sec)
A ball is thrown upward with an initial velocity of 96 ft/sec from the top of a 100ft bridge. Determine the time that it takes for the ball to get to a height of 200ft.
round answers to two decimals, seperated by a comma.
Answer provided by our tutors
sol. s =100ft h=200ft v=96 ft/sec
by formula
-16t^2 +96t+100 =200
=> -16t^2 + 96t -100 =0
=> t^2 -6t +6.25=0
=> t = 4.65 s and 1.34 s