Problema Solution
If an object is thrown straight up from the top of a 240 foot tall building at 88 feet per second, the height of the object ater t seconds can be modeled by the equation h(t)= -16t^2+88+240. What is the maximum height of the object?
Answer provided by our tutors
At Maximum height d(h)/dt = 0.
dh/dt = -32t =0
Or t =0
SO, h(0) = 88+240 = 328 feet