Problema Solution
Pat is 20 years older than his son Patrick. In 2 years Pat will be twice as old as Patrick. How old are they now?
Answer provided by our tutors
Variables:
Let a = Pat's age
Let b = Patrick's age
Given: Pat is 20 years older than his son Patrick.
Means: a = b + 20
Given: In 2 years Pat will be twice as old as Patrick
Means: a + 2 = 2(b + 2)
You have 2 equations.
a = b + 20
a + 2 = 2(b + 2)
Substitute a with b + 20 in the second equation.
a + 2 = 2(b + 2)
b + 20 + 2 = 2(b + 2)
b + 22 = 2(b + 2)
Expand the RHS.
b + 22 = 2(b) + 2(2)
b + 22 = 2b + 4
Subtract b from both sides
b + 22 - b = 2b + 4 - b
22 = b + 4
Subtract 4 from both sides.
22 - 4 = b + 4 - 4
18 = b
Plug this into the first equation to find a.
a = b + 20
a = 18 + 20
a = 38