Problema Solution
The length of a rectangle is 5yd more than twice its width and the area of the rectagle is 88yd^2 find the dimensions of the rectangle
Answer provided by our tutors
(2x+5)(x)=88
2x^2+5x-88=0
[-5 +/- (25-(4)(2)(-88))^1/2]/4
22/4 = 5.5
16*5.5=88
length is 16, width = 5.5