Problema Solution
the sum of three numbers is 18. The sum of twice the first number, 3 times the second number, and 4 times the third number is 53. The difference between 5 times the first number and the second number is 30. Find the three numbers
Answer provided by our tutors
let no are x,y,z
=> x + y+ z = 18
=> 2x + 3y + 4z = 53
=> 5x - y = 30
=> y = 5x-30
=> 6x + z = 48
=> 17x + 4z = 143
=> 24x + 4z = 192
=> 7x = 49
=> x = 7
=> y = 5
=> z = 6