The mean height of women in a country (ages 20-29) is 63.9 inches. A random sample of 75 women in this age group is selected. What is the probability that the mean height for the sample is greater than 64 inches? Assume the standard deviation is =2.83

The probability that the mean height for the sample is greater than 64 inches is _0.3798___?

Solution:

Z-score = (64-63.9)/(2.83/sqrt(75))= 0.306

P(x'>64)=P(Z>0.306) = 0.3798

So the answer is 0.3798