Problema Solution
The speed of train A is 10 mph slower than the speed of train B. Train A travels 190 miles in the same time it takes train B to travel 240 miles. Find the speed of each train.
Answer provided by our tutors
First we know that the time is in common and that we need to use the speed equation (s=d/t) because we are dealing with speeds. We then need to find the speed and distance both trains have in the same amount of time.
----SPEED-----DISTANCE
A: B-10--------------190
B: B-------------------240
Now we can solve for 't' in the speed equation with the two sets of information and set them equal to each other because it the question says it takes the same time.
s = d/t
t = d/s
t = 190/(B-10)------t = 240/B
190/(B-10) = 240/B
190B = 240(B-10)
190B = 240B - 2400
2400 = 240B - 190B
2400 = 50B
48 mph = B
A = B - 10
A = 48 - 10
A = 38 mph
Therefore the speeds of the trains are 38 mph for Train A and 48 mph for Train B.