Problema Solution
two planes which are 1755 miles apart fly towards each other. Their speeds differed by 35mph. If they pass each other in 3 hours, what is the speed of each
Answer provided by our tutors
let 'v' represent the speed of the slower plane, then 'v+35' represents the speed of the faster plane
the planes cover 1755 miles at a combined speed of 'v + v + 35'
distance = speed * time
time = distance /speed
their time in flight, three hours, is then:
3=1755/(2v+35)
solving for 'v' we have v=275
275+35 = 310
the slower plane is travelling at 275mph, the faster plane is travelling at 310mph