Problema Solution
The John Hancock Center tapers as it rises. The top floor is rectangular and has perimeter 520 ft. The width of the top floor measures 20 ft more than one-half its length. What are the dimensions of the top floor?
Answer provided by our tutors
perimeter = twice the sum of the length and width
let 'l' represent its length, then '(l/2)+20' represents its width and we have:
520 = 2(l + (l/2)+20)
solving for 'l' we have l=160
(160/2)+20 = 80+20 = 100
the length of the top floor is 160 ft and its width is 100 ft