Problema Solution
Basketball concession stand sells soda for $1.50, a bag of popcorn for $1.00 and a candy bar for $1.25. At one game, 20 fewer candy bars were sold than bags of popcorn. That same night the number of sodas sold was 10 more than the number of candy bars and bags of popcorn altogether. If the concession stand made $149 that night, how many of each item were sold?
Answer provided by our tutors
Let 's', 'p', and 'c' stand for the number of sodas, number of popcorn bags, and number of candy bars respectively. Then we can write:
1.5s+1p+1.25c=149
('the concession stand made $149 that night')
p=c+20
('20 fewer candy bars were sold than bags of popcorn')
s=c+p+10
('number of sodas sold was 10 more than the number of candy bars and bags of popcorn altogether')
Using Algebrator to solve for 'c', 'p', and 's', we get:
c=16
p=36
s=62