Problema Solution
for an experiment, a student requires 150ml of a solution that is 8%. The storeroom has only solution that are 10% and 5% Nacl. How many ml's of each available solution should be mixed to get 150 ml of 8% NACl
Answer provided by our tutors
From the given information, we can write the following:
x(.1)+(150-x)(.05)=150(.08)
where 'x' represents the number of ml of the 10% solution needed and '10-x' represents the number of ml of the 5% solution needed to make 150ml of 8% solution.
Using Algebrator to solve for 'x', we get:
x=90 ml
Likewise,
10-x=150-90=60ml
Therefore, 90ml of the 10% solution and 60ml of the 5% solution are needed.