Problema Solution
the eletric current I, is amperes, in a curcuit varies directly as the voltage V. When 12 volts are applied, the current is 4 amperes. What is the current when 18 volts are applied?
Answer provided by our tutors
directly varying relationship:
I = kV
we solve for 'k' knowing V=12 when I=4
4 = k12
k = 4/12 = 1/3
when 18V is applied:
I = 1/3 * 18V = 6A
a current of 6A when 18V are applied