Problema Solution
a newspaper carrier has $4.80 in change. He has seven more quarters than dimes but four times as many nickels as quarters. How many coins of each type does he have?
Answer provided by our tutors
let 'x' represent the number of dimes, then 'x+7' represents the number of quarters and '4(x+7)' represents the number of nickels
4.80 = 0.1x + 0.25(x+7) + 0.05(4(x+7))
solving for 'x' we have x=3
3+7=10
4(3+7)40
there were 3 dimes, 10 quarters and 40 nickels