Problema Solution
My number has a tens digit that is 8 more than the ones digit. Zero is not one of my digits.
Answer provided by our tutors
we assume the number is two-digits long, then let 'x' represent the ones digit and 'x+8' represents the tens digits
we require x+8 < 10 in order to be a single-digit
x < 2 and since x can not equal 0, x must be 1
1+8=9
the number is 91