Problema Solution
The length of a rectangle is 31 inches greater than twice the width. If the diagonal is 2 inches more than the length, find the dimensions of the rectangle.
Answer provided by our tutors
Let 'l' stand for length and 'w' stand for width. By definition, we know that the diagonal equals:
diagonal=sqrt(l^2+w^2)
From the question, we can write:
l=2w+31
sqrt(l^2+w^2) =l+2
Solving for 'l' and 'w', we get:
l=63 inches
w=16 inches