Problema Solution
a swimming pool is in the shape of a rectangle the length of the pool is 15 feet more than the width a concrete deck 6 feet wide is added around the pool and the outer perimeter of deck is 178 feet
Answer provided by our tutors
let 'w' represent the width, then 'w+15' represents the length
presumably we are being asked to solve for the dimensions of the swimming pool, although the question completely leaves that information out
perimeter = 2(l+w) where 'l' is length and 'w' is width
with the concrete deck added, our total width is 'w+6' and the total length is 'w+21'
178 = 2(w+6 + w+21)
solving for 'w' we have w=31
31+15 = 46
the dimensions of the swimming pool itself are 31 feet wide, 46 feet long