Problema Solution
A ball is thrown upward with an initial velocity of 80 ft/s from a height 800 ft. h= -16t^2+80t+800. After how many seconds will the ball reach the ground?
Answer provided by our tutors
thrown at a height of 800 feet, we want to solve the equation for 't' when the height is equal to -800
-800 = -16t^2 + 80t + 800
solving for 't' we have a positive value of t=12.807
it will take approximately 12.8 seconds for the ball to reach the ground