Problema Solution
a ball is thrown upward with an initial velocity of 96 ft/s from a height 640 ft. h= -16t^2+96t+640. After how many seconds will the ball hit the ground?
Answer provided by our tutors
the ground is at a height of -640 ft
-640 = -16t^2 + 96t + 640
solving for 't' we have a positive value of t=12.43
the ball will hit the ground in approximately 12.4 seconds