let 'w' represent the width, then 'w+9' represents the length

perimeter = 2(l+w), where 'l' and 'w' represent length and width

118 = 2(w + w+9)

solving for 'w' we have w=25

25+9=34

the width is 25 cm, the length is 34 cm

Let 'l' and 'w' stand for length and width. We can write:

l=w+9 (The length of a rectangle is 9cm more than the width)

2l+2w=118 (the perometer of the rectangle is 118cm)

Using Algebrator to solve for 'l' and 'w', we get:

l=34

w=25