Problema Solution
Hooke's law states that the distance a spring stretches is directly proportional to the weight attached to the spring. If a 30-pound weight attached to the spring stretches the spring 5 inches, find the distance that a 45-pound weight attached to the spring stretches the spring.
Answer provided by our tutors
Using the general equation F=-kx, we can write:
30=-k5
k=-6
45=-(-6)x
x=7.5 inches
Therefore, the spring would stretch 7.5 inches.
30/5 = 45/x
solving for 'x we have x=7.5
a 45-pound weight would stretch the spring 7.5 inches