Problema Solution
A rectangle has a length twice the side of a square, and a width three times less than the side of the square. If the two areas are equal, what are the dimensions of the square?
Answer provided by our tutors
let 'x' represent the length of the square's side, then '2x' represents the length of the rectangle and 'x/3' represents the width of the rectangle
area = l*w where 'l' and 'w' represent length and width
area of the square:
A = x^2
area of the rectangle:
A = (2x)(x/3) = (2/3)x^2
we set their area expressions equal to each other an and solve for 'x':
x^2 = (2/3)x^2
x=0
therefore, such a scenario is not possible, as the square would have sides equal to 0