Problema Solution
a cylindrical glass tube 11.6 cm in length is filled with mercury (density=13.6 g/mL). (the volume of a cylinder of radius r and length h iv V=πr^2h) The mass of mercury needed to fill the tube is 106.1g. calculate the diameter of the inner tube.
Answer provided by our tutors
V = PI*r^2*h
we are given that h = 11.6cm
106.1 grams / 13.6(grams/mL) = 7.801 mL
the volume of the tube is therefore 7.8 mL
11.6 cm * 1000mm/100cm = 116 mm
7.8mL = PI * r^2 * 116mm
solving for 'r' we have a positive value of r=0.1469 mm
0.14mm * (100cm/1000mm) = 0.014 cm
diameter = 2 * radius = 2 * 0.014 = 0.028
the tube has a diameter of 0.028 cm