Problema Solution
A rectangular parcel of land is 20 ft longer than it is wide. Each diagonal between opposite corners is 100 ft. What are the dimensions of the parcel?
Answer provided by our tutors
let 'w' represent the width, then 'w+20' represents the length
the diagonal of the box will be the hypotenuse of a right-triangle with 'w' and 'w+20' for the two legs:
100^2 = w^2 + (w+20)^2
solving for 'w' we have a positive value of w=60
60+20=80
the land is 60 feet wide and 80 feet long