Problema Solution
The sum of three numbers is 18. The sum of twice the first number, 3 times the second number, and 4 times the third number is 59. The difference between 6 times the first number and second number is 11. Find the three numbers.
First Number:
Second Number:
Third Number:
Answer provided by our tutors
let 'a', 'b' and 'c' represent the three numbers, then we have these equations:
a+b+c = 18
2a+3b+4c=59
6a-b=11
solving this system of equations, we have:
first number: 3
second number: 7
third number: 8