Problema Solution
the perimeter of a rectangle is 52. The length is the sum of twice the width and five. Find the length and width of the rectangle
Answer provided by our tutors
let 'w' represent the width, then '2w+5' represents the length
perimeter = 2(l+w), where 'l' and 'w' represents length and width, respectively
52 = 2(w+2w+5)
solving for 'w' we have w=7
2*7+5 = 19
the rectangle is 7 units wide and 19 units long