Problema Solution
How many milliliters of a 12% acid solution and how many milliliters of a 4% acid solution must be mixed to obtain 40 mL of a 10% acid solution?
Answer provided by our tutors
We can write:
.12n+.04(40-n)=.1(40)
Where 'n' is the amount of 12% solution needed and '40-n' is the amount of 4% solution needed. solving for n, we get:
n=30 ml
40-n=10 ml
therefore we need 30 mL of 12% solution and 10 mL of 4% solution.