Problema Solution
The product of some negative number and 3 less than twice that number is 527.Find the number.
Answer provided by our tutors
Let some number = n
some negative number = (-n)
3 less than twice that number = (2(-n)-3)
set it up into an equation:
(-n)(2(-n)-3)=527
factor the (-n) into (2(-n)-3)
2n2 +3n = 527
Subtract 527
2n2 +3n - 527= 0
Common factors of 527 are 31 and 17 so factor the equation:
(2n-31)(n+17)=0
Solve for each individual factor = 0
2n-31=0 ; n+17 = 0
n = 16 ; n = -17