Problema Solution
The length of a rectangle is 6 more than the width. If the area of the rectangle is numerically 131 more than its perimeter, what are the dimensions of the rectangle?
Answer provided by our tutors
let 'w' represent the width, then 'w+6' represents the length
area = length * width
perimeter = 2(length + width)
w(w+6) = 131 + 2(w + w+6)
solving for 'w' have a positive value of w=11
11+6=17
the width of the rectangle is 11 ft, its length is 17 ft