Problema Solution
What quantity of a 50% acid solution must be mixed with a 30% solution to produce 200 mL of a 45% solution?
Answer provided by our tutors
let 'x' represent the amount in mL of 50% acid solution used, then '200-x' represents the amount of 30% solution used
0.45(200) = 0.50x + 0.30(200-x)
solving for 'x' we have x=150
200-150 = 50
50 mL of 30% solution should be mixed with 150 mL of 50% solution