Problema Solution
the sum of three numbers is 21. the sum of twice the first number, 5 times the second number, and 6 times the third number is 94. the difference between 3 times is the first number and the second number is 10. find the three numbers
Answer provided by our tutors
let 'a', 'b' and 'c' represent the three numbers
a+b+c=21
2a+5b+6c=94
3a-b=10
solving this system we have:
a = 6
b = 8
c = 7
the numbers are 6, 8 and 7