Problema Solution
find three consecutive odd integers such that the sum of the first, two times the second, and three times the third is 82
Answer provided by our tutors
let '2n+1' represent the first odd integer, then '2n+3' and '2n+5' represent the next two consecutive odd integers
(2n+1) + 2(2n+3) + 3(2n+5) = 82
solving for 'n' we have n=5
2*5+1 = 11
the consecutive odd integers are 11, 13, and 15