Problema Solution
1. The width of a rectangle is 7 less than twice its length. If the area of the rectangle is 21 "cm"^2, what is the length of the diagonal?
The length of the diagonal is cm.
Give your answer to 2 decimal places.
a^2+b^2=c^2
2. The equation x^2+8x-14=0 has two solutions A and B where A
Answer provided by our tutors
please submit one problem at-a-time, we answer problem #1 here
let 'l' represent the length, then 'l-7' represents the width
area = length * width
21 = l(l-7)
solving for 'l' we have a positive value of l=9.266
9.266 - 7 = 2.266
length of the diagonal is the hypotenuse of a right triangle with sides 'l' and 'w':
diagonal length = sqrt(2.266^2 + 9.266^2) = 9.539
the length of the diagonal is approximately 9.54 cm