Problema Solution
Find two consecutive positive integers such that the sum of their squares is 421.
Answer provided by our tutors
let 'n' represent the first positive integer, then 'n+1' represents the next consecutive positive integer
421 = n^2 + (n+1)^2
solving for 'n' we have a positive value of n=14
14+1=15
the numbers are 14 and 15