Problema Solution
A man driving at 15 m/s sees someone he immediately accelerates at 3m/s2 if he does this for 18 secs what speed will he be going on contact?
Answer provided by our tutors
First, we write down what we are given:
v_o=15 m/s
a=3 m/s^2
t=18s
We will use the following kinematic equation to solve this question:
v=v_o + at
Plugging in our numbers we get:
v=15+3(18)
Solving, we get:
v=69 m/s